Physics, asked by kajalsheel, 1 year ago

ques no 34..plz tell...

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Answered by medhashivani03
1
s=usinQt+1/2 gt^2
so,40=20*1/2t+1/2*10*t^2
solvinf this u will get a quadratic equation
t^2+2t-8                                                            (pls consider my Q as theta)

on solving this u will get t as 4sec
now horizontal range is ucosQ*t
which is 20rootunderof3/2*4
which will give 40 rootunderof 3

kajalsheel: nice..
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