find the exact value by using a half-angle identity.
sin 22.5degrees
show your work. thanks!
Answers
Answered by
13
Let Ф = 22.5°
⇒2Ф = 45°
so cos(2Ф) = 1 - 2sin²Ф
⇒ cos 45 = 1 - 2 sin²(22.5)
⇒ 1/√2 = 1 - 2 sin²(22.5)
⇒ (1 - 1/√2)/2 = sin²(22.5)
⇒ sin²(22.5) = (√2 - 1)/2√2
⇒ sin (22.5) = √{(√2 - 1)/2√2}
⇒sin (22.5) = √{(2 - √2)}/2
or
⇒2Ф = 45°
so cos(2Ф) = 1 - 2sin²Ф
⇒ cos 45 = 1 - 2 sin²(22.5)
⇒ 1/√2 = 1 - 2 sin²(22.5)
⇒ (1 - 1/√2)/2 = sin²(22.5)
⇒ sin²(22.5) = (√2 - 1)/2√2
⇒ sin (22.5) = √{(√2 - 1)/2√2}
⇒sin (22.5) = √{(2 - √2)}/2
or
Anonymous:
hope this helps
Answered by
0
Answer:
route 2 -2 is the answer
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