Question

Find the excluded values of y/y^2-25. Is....

Answer 1

Step-by-step explanation:

= y/(y2 - 25)

y2 - 25 = y2 - 52

= (y - 5)(y + 5)

= y/(y + 5) (y - 5)

By equating the denominator equal to zero, we get y + 5 = 0 and y - 5 = 0.

y + 5 = 0 and y - 5 = 0

y = -5 and y = 5

So, the excluded values are -5 and 5.

Answer 2

Answer:

-5 and 5

i hope it helps uu