Find the excluded values of y/y^2-25. Is....
Answers
Answered by
8
Step-by-step explanation:
= y/(y2 - 25)
y2 - 25 = y2 - 52
= (y - 5)(y + 5)
= y/(y + 5) (y - 5)
By equating the denominator equal to zero, we get y + 5 = 0 and y - 5 = 0.
y + 5 = 0 and y - 5 = 0
y = -5 and y = 5
So, the excluded values are -5 and 5.
Answered by
3
Answer:
-5 and 5
i hope it helps uu
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