Math, asked by madhangi03, 11 months ago

Find the excluded values of y/y^2-25. Is....

Answers

Answered by priyankaroykhan888
8

Step-by-step explanation:

= y/(y2 - 25)

y2 - 25 = y2 - 52

= (y - 5)(y + 5)

= y/(y + 5) (y - 5)

By equating the denominator equal to zero, we get y + 5 = 0 and y - 5 = 0.

y + 5 = 0 and y - 5 = 0

y = -5 and y = 5

So, the excluded values are -5 and 5.

Answered by likhitha25
3

Answer:

-5 and 5

i hope it helps uu

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