Question

find the expansion of (2a+3b+4c)²​

Answer 1

Answer:

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Step-by-step explanation:

We know,

(x+y+z)^2 = x^2+y^2+z^2+2xy+2yz+2zx [Identity]

Here,

x=2a

y=3b

z=4c

Putting Values in Identity, We get :

⇒(2a+3b+4c)^2=(2a)^2+(3b)^2+(4c)^2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

⇒4a^2+9b^2+16c^2+12ab+24bc+16ca

Answer 2

Answer:

4a^2+9b^2+16c^2+12ab+24bc+16ca

Step-by-step explanation:

(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca

(2a)^2+(2b)^2+(2c)^2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

4a^2+9b^2+16c^2+12ab+24bc+16ca