Question

Find the expansion of ( x+5) (x-3) (x-7) using proper identity​

Answer 1

Answer:

x³ - 5x² - 29x + 105

Step-by-step explanation:

(x+5) (x-3) (x-7)

[ ( x+5) (x-3) ] ( x-7 )

(x² - 3x + 5x - 15) ( x-7 )

(x² + 2x -15 ) ( x-7 )

x³ + 2x² - 15x - 7x² - 14x + 105

⇒x³ - 5x² - 29x + 105