Math, asked by aastha15das, 1 year ago

find the expression whose square is (2x^2-xy-15y^2) (4x^2-25y^2) (2x^2-11xy+15y^2).

Answers

Answered by allysia

To find it's root we will first factorise it :
(2x^2 -xy-15y^2)(4x^2-25y^2)(2x^2 -11xy+ 15y^2)
= ( 2x^2 -6xy + 5xy -15y^2) {(2x)^2 - (5y)^2}
( 2x^2 -6xy -5 xy + 15 y^2)
= {2x ( x - 3y) + 5y (x -3y)}( 2x-5y)(2x+5y)
{ 2x (x -3y) - 5y (x-3y)}
= (2x +5y) (x- 3y)(2x -5y)(2x+5y)(2x -5y)(x-3y)
Now, to we have to find it's square root

=√{(2x +5y) (x- 3y)(2x -5y)(2x+5y)(2x -5y)(x-3y)}
Which equals
(2x +5y) (x- 3y)(2x -5y).

Answered by Anonymous

Answer:

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To find it's root we will first factorise it :

(2x^2 -xy-15y^2)(4x^2-25y^2)(2x^2 -11xy+ 15y^2)

= ( 2x^2 -6xy + 5xy -15y^2) {(2x)^2 - (5y)^2}

( 2x^2 -6xy -5 xy + 15 y^2)

= {2x ( x - 3y) + 5y (x -3y)}( 2x-5y)(2x+5y)

{ 2x (x -3y) - 5y (x-3y)}

= (2x +5y) (x- 3y)(2x -5y)(2x+5y)(2x -5y)(x-3y)

Now, to we have to find it's square root

=√{(2x +5y) (x- 3y)(2x -5y)(2x+5y)(2x -5y)(x-3y)}

Which equals

(2x +5y) (x- 3y)(2x -5y).

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