Question

find the factor of p(y) of thr eqn P(y)=y^3+4y^2+y-6

Answer 1

Answer:

(1): "y2"   was replaced by   "y^2".  1 more similar replacement(s).

STEP1:Equation at the end of step 1

STEP2:

y3 - 4y2 + 7y - 6 Simplify ————————————————— y - 2

Checking for a perfect cube :

 2.1    y3 - 4y2 + 7y - 6  is not a perfect cube

Trying to factor by pulling out :

 2.2      Factoring:  y3 - 4y2 + 7y - 6 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  7y - 6 

Group 2:  y3 - 4y2 

Pull out from each group separately :

Group 1:   (7y - 6) • (1)

Group 2:   (y - 4) • (y2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

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