Question

find the factor of (x²-8x-20)​

Answer 1

x2-8x=20

Two solutions were found :

x = 10

x = -2

Rearrange:

x^2-8*x-(20)=0

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1 Factoring x2-8x-20

The first term is, x2 its coefficient is 1 .

The middle term is, -8x its coefficient is -8 .

The last term, "the constant", is -20

Step-1 : Multiply the coefficient of the first term by the constant 1 • -20 = -20

Step-2 : Find two factors of -20 whose sum equals the coefficient of the middle term, which is -8 .

-20 + 1 = -19

-10 + 2 = -8 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and 2

x2 - 10x + 2x - 20

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-10)

Add up the last 2 terms, pulling out common factors :

2 • (x-10)

Step-5 : Add up the four terms of step 4 :

(x+2) • (x-10)

Which is the desired factorization

Equation at the end of step 1 :

(x + 2) • (x - 10) = 0

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Answer 2

Answer:

x2-10x+2x-20

x(x-10)+2(x-10)

(x-10),(x+2)