Question

Find the factor: x^2- 2xy + y^2 + 3x - 3y + 4 = 0.

Answer 1

Hey buddy,
I hope u understand my answer

$x {}^{2} - 2xy + y {}^{2} + 3x - 3y + 4 = 0 \\ we \: can \: write \: x {}^{2} - 2xy + y {}^{2} as \\ (x -y) {}^{2} \\ so \: (x - y) {}^{2} + 3x - 3y + 4 = 0 \\ (x - y)(x - y) +( 3 + x - y) + 4 = 0 \\ (x - y)(x - y + 3) + 4 = 0 \: is \: your \: answer$