find the factors of 1+64x^3
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Answer:
cline1−2
Given:
\cline1−2
To find:
\cline1−2
Solution:
\cline1−2
Answer:
\cline1−2
1+64x
3
Factors of 1+64x
3
Consider
1+64x
3
=1
3
+4
3
x
3
=1
3
+(4x)
3
Using the identity
a
3
+b
3
=(a+b)(a
2
−ab+b
2
)
=(1+4x)(1
2
−4x+(4x)
2
)
=(1+4x)(1−4x+16x
2
)
Factors of 1+64x
3
are (1+4x) and (1−4x+16x
2
)
Factorise 8x^3+y^3+z^3-6xyz using identity
Factorise 4 x square + 9 y square + 16 z square + 12 x y - 24 Y Z - 16 X Z
Hope it helps you
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