Question

find the factors of = 2x^2-7x+3

Answer 1

Answer:

(2x-1) (x-3)

Explanation

In 2x^2-7x+3, first digit is +2x and last digit is +3.

So 2x*3=6x Now middle number is -7x

So -7x= -6x-x

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Step By Step Solution:

2x^2-7×+3 = 2x^2-1x-6x+3

x (2x-1) -3 (2x-1)

(2x-1) (x-3) ans.