Question

find the factors of 3x^3+2x^2-3x-2

Answer 1

Answer:

x = +-1 and x = 1/3

Step-by-step explanation:

$3x^{3} +2x^{2} -3x-2\\=>3x^{3}-3x+2x^{2} -2\\ =>3x(x^{2} -1)+2(x^{2} -1)\\=>(x^{2} -1)(3x-1)\\=> x=+ or -1 and x = \frac{1}{3}$

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Answer 2

3x³+2x²-3x-2

=x²(3x+2)-1(3x+2)

=(3x+2)(x²-1)

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