Question

Find the factors of: 4x2 – 8x + 4​

Answer 1

Answer:

$4 {x}^{2} - 8x + 4 = 0 \\ 4( {x}^{2} - 2x + 1) = 0 \\ {x}^{2} - 2x + 1 = \\ {x}^{2} - 1x - 1x + 1 = 0 \\ x(x - 1) - 1(x - 1) = 0 \\ (x - 1)(x - 1) = 0 \\ x = 1 \: or \: 1.$