Question

find the factors of 8 - y^3​

Answer 1

$\underline{\textbf{Given:}}$

$\mathsf{8-y^3}$

$\underline{\textbf{To find:}}$

$\mathsf{The\;factors\;of\;8-y^3}$

$\underline{\textbf{Solution:}}$

$\underline{\textbf{Formula used:}}$

$\boxed{\mathsf{a^3-b^3=(a-b)(a^2+ab+b^2)}}$

$\mathsf{Consider}$

$\mathsf{8-y^3}$

$\textsf{This can be written as,}$

$\mathsf{=2^3-y^3}$

$\mathsf{=(2-y)(2^2+2y+y^2)}$

$\mathsf{=(2-y)(4+2y+y^2)}$

$\mathsf{=(2-y)(y^2+2y+4)}$

$\underrline{\textbf{Answer:}}$

$\mathsf{The\;factors\;of\;8-y^3\;are\;2-y\;and\;y^2+2y+4}$

$\underline{\textbf{Find more:}}$

1.x^2-(a-1/a)x+1 factorise the following

https://brainly.in/question/4301404

2.Factorise x^4-(x-z)^4​

https://brainly.in/question/14993176

Answer 2

Answer:

Answer is attached.

Hope it helps...