Question

Find the factors of a^2 (b + c) + b^2(c + a) + c^2(a + b)
- 2b²c.​

Answer 1

Answer:

a^2(b+c)+b^2(c+a)+c^2(a+b)+2abc 

= a^2 b+ a^2c + b^2 c+ ab^2+c^2a+bc^2+2abc

= a(b^2+ 2bc+c^2) + a^2 b+ a^2c + b^2 c +bc^2

= a(b+c)^2 + a^2(b+c) + bc(b+c)

= (b+c) [ a^2 +a(b+c)+ bc]

= (b+c) (a +b)(c+a)