Question

find the factors of the polynomial y²-4√3y-15?​

Answer 1

f(v)=v²+4√3v-15

=v²+5√3v-√3v-15

=v(v+5√3)-√3(v+5√3)

=(v-√3)(v+5√3)

so,√3,-5√3 are the zeros of the given polynomial.

I hope this will help u 

Answer 2

Step-by-step explanation:

${y}^{2} - 4 \sqrt{3} y - 15$

5√3 × -√3 =>-15 So

${y}^{2} - 5 \sqrt{3} y + \sqrt{3}y - 15 = >$

$y(y - 5 \sqrt{3}) + \sqrt{3}(y - 5 \sqrt{3} ) = >$

$(y + \sqrt{3})(y - 5 \sqrt{3})$

Hence

(y+√3) and (y-5√3) are factors of the polynomial

${y}^{2} - 4 \sqrt{3}y - 15$

Hope it helps you.