Math, asked by nemoimran23, 3 months ago

find the factors of : (x-2y)³ - 64z³​

Answers

Answered by ruby932
0

Step-by-step explanation:

(x-2y)^3 - 64z^3

(x-2y)^3 - (4z)^3

a^3-b^3= (a-b) (a^2+ab+b^2)

= (x-2y-4z) [ (x-2)^2 + (x-2y×4z) + (4z)^2]

= (x-2y-4z) [ (x^2+2^2-2× x × 2) + (4xz-8yz) +16z^2]

= (x-2y-4z) (x^2+4-2x+4xz-8yz+16z^2)

HOPE IT HELPS!!

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