Question

Find the factors of (x²-x)²-8(x²-x)+12 *


1) (x-2)(x+1)(x+3)(x-2)

2) (x-2)(x+1)(x-3)(x+2)

3) (x-2)(x+1)(x-3)(x-2)
​

Answer 1

Answer:

How can I factor (x²+x−5)(x²+x−7)+1 ?

First method:::::::::::::

[x^2+x—5] [x^2+x—7]+1

=[x^2+x—5] [x^2+x—5 —2]+1

Suppose [x^2+x—5]=a

= a[a—2]+1

=a^2–2a+1

=a^2—a—a+1

=a[a—1] —1[a—1]

=[a—1][a—1]

=[a—1]^2

Now put the value of a

= [x^2+x—5–1]^2

=[x^2+x—6]^2

=[x^2+3x—2x—6]^2

=[x{x+3]—2{x+3}]^2

=[x—2]^2 .[x+3]^2

Second method::::::::::::

[x^2+x—5] [x^2+x—7]+1

=[x^2+x—6+1][x^2+x—6–1]+1

=[x^2+x—6]^2 —[1]^2 +1

=[x^2+x—6]^2

=[x—2]^2 .[x+3]^2

HOPE THIS HELPS.

Answer 2

Step-by-step explanation:

option 3 is the correct answer

follow me for more explanation