Question

Find the final velocity of the ball that is dropped from the second floor if the ball takes 18 seconds before hitting the ground. The acceleration due to gravity is g = 9.80 m.s-2.

Answer 1

$\blue{\boxed{Answer:-}}$

From equations of motion:

v=u+at

where,

v=final velocity

u=initial velocity

a=acceleration[Here, a=g(acceleration due to gravity ie 9.8m/s²)]

t=time taken

Answer:

v=u+at

⇒v=0+9.8*18 [Here, u=0 as it has been considered that the ball was at rest before being thrown]

⇒v=176.4m/s²

Ans=v=176.4m/s²

Answer 2

Answer:

From equations of motion:

v=u+at

where,

v=final velocity

u=initial velocity

a=acceleration[Here, a=g(acceleration due to gravity ie 9.8m/s²)]

t=time taken

Answer:

v=u+at

⇒v=0+9.8*18 [Here, u=0 as it has been considered that the ball was at rest before being thrown]

⇒v=176.4m/s²

Ans=v=176.4m/s²

Explanation: