Question

find the find the value of 1 upon 3 power minus 2

Answer 1

$\dfrac{1}{3^{-2}}=9$

Given data:

The number $\dfrac{1}{3^{-2}}$

To find:

Value of the given number

Concept:

$a^{-1}=\dfrac{1}{a}$

$a^{b\times c}=a^{bc}$

Step-by-step explanation:

Now, $\dfrac{1}{3^{-2}}$

= $(3^{-2})^{-1}$

• using $a^{-1}=\dfrac{1}{a}$

= $3^{(-2)\times (-1)}$

= $3^{2}$

• since $(a^{b})^{c}=a^{bc}$

• since $a^{b\times c}=a^{bc}$

= 9

Read more on Brainly.in

Which of these has the lowest value? a. 888+8 b. 999+9 c. 444+4

https://brainly.in/question/8171807

The value of( 1.004)1/2 is

https://brainly.in/question/17334815

#SPJ3

Answer 2

Answer:

$\frac{1}{ {3}^{ - 2} } = 9$

Step-by-step explanation:

given

$\frac{1}{ {3}^{ - 2} } \\ \\ = \frac{1}{ \frac{1}{ {3}^{2} } } \\ \\ = \frac{1}{ \frac{1}{9} } \\ \\ = 9$