find the first 4 term of an ap where a= 5 ;d= 2
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given a=5
d=2
=a2
=a+d
=5+2
=7
=a3
=a+2d
=5+2×2
=9
=a4
=a+3d
=5+3×2
=11
d=2
=a2
=a+d
=5+2
=7
=a3
=a+2d
=5+2×2
=9
=a4
=a+3d
=5+3×2
=11
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