Find the first 4 terms of an AP whose first term is -2 and common difference is -3
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First term is -2=a
common differnce =-3=d
a=-2
second term = a+d=-2-3=-5
third term = a+2d=-2-6=-8
fourth term =a+3d=-2-9=-11
so AP is.......
-2,-5,-8,-11
common differnce =-3=d
a=-2
second term = a+d=-2-3=-5
third term = a+2d=-2-6=-8
fourth term =a+3d=-2-9=-11
so AP is.......
-2,-5,-8,-11
Answered by
2
Answer:
Step-by-step explanation:
Given ::- a = -2
d = -3
To find ::- first 4 terms of an AP
Solution ::-
a = -2
Second term = a + d
= -2 + (-3)
= -2 -3 = -5
Similarly,
Third term = -5 -3 = -8
Fourth term = - 8 -3 = -11
Therefore the first four terms of an AP are
-2 , -5 , -8 , -11
HOPE IT HELPS YOU!!
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