Find the first and last term of an AP whose middle term is 8
Zenishtha:
It think the question is find the 'sum' of the first and last term....
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There is only one middle term. Therefore, total no of terms is odd.
Now,
a(n+1/2)= a + (n+1/2 - 1) d
8 = a + (n-1/2)d
16 = 2a + (n-1)d [Taking 2 as the LCM]
16 = a + an.
Sum of first and last term is 16.
Therefore,
a = 16- an
an= 16-a
Hope it helped!
NISHTHA.
Now,
a(n+1/2)= a + (n+1/2 - 1) d
8 = a + (n-1/2)d
16 = 2a + (n-1)d [Taking 2 as the LCM]
16 = a + an.
Sum of first and last term is 16.
Therefore,
a = 16- an
an= 16-a
Hope it helped!
NISHTHA.
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