Question

find the first four terms of an A.P whose first term is 12 & common difference is -4​

Answer 1

a=12

d=-4

a4=a+(n-1)d

a4=12+(4-1)-4

a4=12-12

a4=0

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Answer 2

a=12 d=-4

T2=a+d=12+(-4)

=12-4

=8

T3=T2+d=8+(-4)

=8-4

=4

T4=T3+d=4+(-4)

=4-4

=0

A.P= 12,8,4,0,......HOPE IT HELP YOU !!!!!!!