Question

find the first, fourth, and the tenth terms of the arithmetic sequence described by the given rule: A(n)=12 + (n-1)(3)
A. 12,24,42
B. 0,9,27
C. 3,24,27
D. 12,21,39

Answer 1

Answer:

D

Step-by-step explanation:

1st term = 12 + (1-1)(3) = 12+0 = 12

4th term = 12 + (4-1)(3) = 12+9 = 21

10th term = 12 + (10-1)(3) = 12+27 = 39

Answer 2

Answer:

D. 12,21,39

Step-by-step explanation:

when n=1,A(1)= 12+(1-1)(3)=12

when n=4,A(4)=12+(4-1)(3)=21

when n=10,A(10)=12+(10-1)(3)=39