Question

Find the first negative term of the following A.P. 130, 123, 116, …​

Answer 1

Answer:

121,117,113.......

a=121. d=-4

For a(n) be negative

a(n)<0

a+(n-1)d <0

121+(n-1)*(4)<0

For ans be negative

(n-1)(-4)>121

4n >(125)

n >125/4

n >31.25

n=32

Therefore the 31st term is the negative term

Verification

a(n)=a+(n-1)d

a(n)=121+(32-1)-4

a(n)=121+31*-4

a(n)=121-124

a (n)=-3

Step-by-step explanation:

please mark as Branliest

Answer 2

Answer:

-3

Step-by-step explanation:

a20 = -3

a20 = 130+(20-1)(-7)

a20 =130+(19×(-7))

a20= 130-133

a20 = -3