Question

Find the first term and common difference for an A.P. are a= 6 &d= 3 respectively.find S10?​

Answer 1

Answer:

sn = n/2 [2a +(n-1)d]

s10 = 10/2 [ 2× 6 +(10-1)3 ]

s10 = 5 ( 12 + 9× 3)

s10 = 5 ( 12 + 27 )

s10 = 5 × 39

s10 = 195

Answer 2

Answer:

Answer:

sn = n/2 [2a +(n-1)d]

s10 = 10/2 [ 2× 6 +(10-1)3 ]

s10 = 5 ( 12 + 9× 3)

s10 = 5 ( 12 + 27 )

s10 = 5 × 39

s10 = 195

Step-by-step explanation:

Hope this answer will help you.