Find the first term and common difference for an A.P. are a= 6 &d= 3 respectively.find S10?
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Answered by
1
Answer:
sn = n/2 [2a +(n-1)d]
s10 = 10/2 [ 2× 6 +(10-1)3 ]
s10 = 5 ( 12 + 9× 3)
s10 = 5 ( 12 + 27 )
s10 = 5 × 39
s10 = 195
Answered by
4
Answer:
Answer:
sn = n/2 [2a +(n-1)d]
s10 = 10/2 [ 2× 6 +(10-1)3 ]
s10 = 5 ( 12 + 9× 3)
s10 = 5 ( 12 + 27 )
s10 = 5 × 39
s10 = 195
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Hope this answer will help you.
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