find the first term and difference of an ap if the sum of first five even terms is 15 and the sum of the first three terms is equal to -3
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Answer:
1st term=-5, difference=4
Step-by-step explanation:
Sum of 1
st
seven terms
15=
2
5
(2a+(5−1)d)
3=a+
2
4d
3=a+2d−(i)
Sum of 1
st
3 terms=3
So,3a+3d=−3 [Considering 1
st
term as a,a+d,a+2d]
a+d=−1−(ii)
Solving (i) & (ii)
d=3−(−1)
d=4
Putting value of d in (ii)
a+4=−1
a=−5
So first term=−5 and difference =4
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