find the first term and the 20th term of an ap whose 5th and 7th term are 13 and 17
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HEY BUDDY..!!!
HERE'S THE ANSWER..
_____________________
♠️ a5 = 13 and a7 = 17 , We have to find a20
⏺️ Now for solving this type of questions , refer the following way.
⏺️We know { an = a + ( n - 1 ) d }
⏺️ a5 = a + 4 d
⏺️a7 = a + 6 d
✔️ a + 4 d = 13_______( 1 )
✔️ a + 6 d = 17_______( 2 )
▶️ Now by ( 2 ) - ( 1 )
=> a + 6 d = 17
=> a + 4 d = 13
( - ) ( - ) ( - )
_____________
=> 2 d = 4
_____________
✔️ [ d = 2 ] ✓ // common difference ( d )
⏺️ Now putting value of d in eqn ( 1 )
⏺️a + 4 d = 13
=> a + 4 ( 2 ) = 13
=> a + 8 = 13
=> a = 13 - 8
=> [ a = 5 ]✓
♠️ Now similarity { a20 = a + 19 d }
=> a20 = a + 19 d
=> a20 = 5 + 19 ( 2 )
=> [ a20 = 43 ]✔️✔️
HOPE HELPED..
JAI HIND..
:-)
HERE'S THE ANSWER..
_____________________
♠️ a5 = 13 and a7 = 17 , We have to find a20
⏺️ Now for solving this type of questions , refer the following way.
⏺️We know { an = a + ( n - 1 ) d }
⏺️ a5 = a + 4 d
⏺️a7 = a + 6 d
✔️ a + 4 d = 13_______( 1 )
✔️ a + 6 d = 17_______( 2 )
▶️ Now by ( 2 ) - ( 1 )
=> a + 6 d = 17
=> a + 4 d = 13
( - ) ( - ) ( - )
_____________
=> 2 d = 4
_____________
✔️ [ d = 2 ] ✓ // common difference ( d )
⏺️ Now putting value of d in eqn ( 1 )
⏺️a + 4 d = 13
=> a + 4 ( 2 ) = 13
=> a + 8 = 13
=> a = 13 - 8
=> [ a = 5 ]✓
♠️ Now similarity { a20 = a + 19 d }
=> a20 = a + 19 d
=> a20 = 5 + 19 ( 2 )
=> [ a20 = 43 ]✔️✔️
HOPE HELPED..
JAI HIND..
:-)
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