Question

Find the first term of an A.P. whose second term is 14 and the common difference 14.​

Answer 1

Answer:

0

Step-by-step explanation:

Given---> Second term of AP = 14

Common difference of AP = 14

To find ---> First term of AP

Solution---> Let first term of AP be a and common difference be d and second term be a₂

ATQ

a₂ = 14 , d = 14 , a = ?

We have a formula of AP

aₙ = a + ( n - 1 ) d

14 = a + ( 2 - 1 ) 14

14 = a + ( 1 ) 14

14 = a + 14

14 - 14 =a

0 = a

a = 0

So first term of given AP = 0

Second method--->

We know that

Common difference = a₂ - a₁

d = a₂ - a₁

Putting d = 14 and a₂ = 14

14 = 14 - a₁

a₁ = 14 -14

a₁ = 0

So first term of given AP is zero

Additional information--->

(1) Sₙ = n / 2 { 2a + ( n - 1 ) d }

(2) Sₙ = n / 2 ( a + l )

Answer 2

Step-by-step explanation:

answer will be 0.

a=0

....hope this is correct