one of the root of quadratic equation is 4-√7.find the equation.
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Answered by
99
One of the root = 4 - √7
Other root will be 4 + √7
(because roots are in pairs)
Sum of roots = (4-√7)+(4+√7) = 8
Product of roots = (4-√7)×(4+√7) = 4^2 - (√7)^2 = 16 - 7 = 9
Equation will be:
x^2 - (sum of roots) x + (product of roots) = 0
=> x^2 - 8x + 9 = 0
Answer: x^2 - 8x + 9 = 0
Other root will be 4 + √7
(because roots are in pairs)
Sum of roots = (4-√7)+(4+√7) = 8
Product of roots = (4-√7)×(4+√7) = 4^2 - (√7)^2 = 16 - 7 = 9
Equation will be:
x^2 - (sum of roots) x + (product of roots) = 0
=> x^2 - 8x + 9 = 0
Answer: x^2 - 8x + 9 = 0
sunny1993:
thanks bro...
Answered by
18
Yes jail skskba sis I don't know only one of the circle in the blanks padh ke ho ra hai
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