find the first term of ap whose second term is 14 and the comman difference is 14
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Answer:
t1=0
Step-by-step explanation:
Given t2=14 d=14
Formula. tn=t1+(n-1)d
t2=t1+(2-1)d
t2=t1+d
14=t1+14
t1=0
Answered by
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Answer:
Further, a, a+d , a+2d . . . .
14,28, 14+28=42 ,all multiplies of 14 and so on
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