Find the first term of the AP series in which 104 term is 6 and 18 term is 70.
Answers
Answered by
1
104th term= 6
a+(104-1)d=6
a+103d=6 ____[i]
Now,
18th term=70
a+17d=70_____[ii]
Now, it is a type of linear equation in two variable, Subtract [i] and [ii]
a+103d-a-17d=6-70
103d-17d=-64
86d=-64
d= - 64/86
= -32/43
Now,putting the value of d in [ii], we get
a+17( -32/43)=70
a-(544/43)=70
43a-544=3010
43a=3554
a=3554/43
a=82.65
I solved according to the given data but I think the question is wrong
Similar questions