Math, asked by bethajaiveerjay, 1 year ago

find the first three terms of a sequence whose nth term is given by tn=2n+1

Answers

Answered by gaurav2013c
14
Tn = 2n +1

=> a+(n-1)d = 2n - 2 + 3

=> a+(n-1)d = 3 + 2(n-1)

On Comparing both sides, we get

a = 3

d = 2


T1 = 3

T2 = a +d = 3 + 2 = 5

T3 = a +2d = 3 + 2*2 = 7

First three terms are 3,5 and 7
Answered by rubisharma84
10
Since nth term is given by tn=2n+1
first term = t1 = 2×1+1 = 3
second term = t 2 = 2×2 +1 = 5
third term = t3 = 2×3 +1 =7
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