Find the first two sequence for an is given below
Sn=n2 (n+1)
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HEYA ...
Answr..
Sn=n^2(n+1)
for n=1
S1= (1)^2(1+1)
=1(2) = 2
for n=2
S2=(2)^2(2+1)
=4(3). = 12
so sequence is...
2,12,....,,.
hope it's helpful
Answr..
Sn=n^2(n+1)
for n=1
S1= (1)^2(1+1)
=1(2) = 2
for n=2
S2=(2)^2(2+1)
=4(3). = 12
so sequence is...
2,12,....,,.
hope it's helpful
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