Question

find the first two terms of the sequence Sn = n^2 (n+1)

Answer 1

Sn= n^2(n+1)
put n = 1
S1=1^2(1+1)
= 1 * 2
S1 =2
S1 means sum first no.
therefore
S1=a1=first term of sequence =3
a1 =3
now
put n=2
S2=2^2(2+1)

=4*3

S2=12

(S2 = a1 + a2)

a1+a2= 12
(a1= ²)
2+a2=12
a2=12-2
=10
hence a1 = 2
a2 = 10
Hope this would had helped you
have good day
sorry for mistake

Answer 2

S1 = A1 = 1 (1+1) = 2

S2 = A1 + A2 = 4 (2+1) = 4×3 = 12

A1 + A2 = 12

so, A2 = 12-2 = 10

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