Find the focus of the parabola whose vertex is at (- 1, 2) and the directrix x + 2y + 1 = 0
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Let P(x,y) be any point on the parabola whose focus is S(−1,−2) and the directrix x−2y+3=0.
Draw PM perpendicular to directrix $$x - 2y + 3 = 0$$
Then by definition SP=PM
⇒SP
2
=PM
2
⇒(x+1)
2
+(y+2)
2
=(
1+4
x−2y+3
)
2
⇒5[(x+1)
2
+(y+2)
2
]=(x−2y+3)
2
⇒5(x
2
+y
2
+2x+4y+5)=(x
2
+4y
2
+9−4xy+6x−12y)
⇒4x
2
+y
2
+4xy+4x+32y+16=0 This is the equation of the required parabola
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