Question

Find the focus of the parabola y2=KX, which passes through the points (1,2)​

Answer 1

Step-by-step explanation:

y2 = kx passes through (4, -2)

(-2)2 = k(4)

⇒ 4 = 4k

⇒ k = 1

y2 = x = 4(

1

4

)x

a =

1

4

Equation of LR is x = a or x – a = 0

i.e., x =

1

4

⇒ 4x = 1

⇒ 4x – 1 = 0

Focus (a, 0) = (

1

4

, 0)