find the following:
[(1/3)^-2+(1/2)^-3]÷(1/4)^-2
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(i) ((1/3)-3 – (1/2)-3) ÷ (1/4)-3 = (33 – 23) ÷ 43 (1/an = a-n) = (27-8) ÷ 64 = 19 ÷ 64 = 19 × 1/64 (1/a ÷ 1/b = 1/a × b/1)
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