Question

Find the following by using Identity-.(a^2-b^2)^2​

Answer 1

Answer:

$a^{4}$ -2a²b² + $b^{4}$

Step-by-step explanation:

(a²-b²)²

Using the identity - (x-y)² = x²-2xy+y²

(a²-b²)² = (a²)² -2a²b² +(b²)²

            = $a^{4}$ -2a²b² + $b^{4}$

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Answer 2

Answer:

$a^{4} -b^{4} -2a^{2}b^{2}$

Step-by-step explanation:

• Given:  $(a^{2} -b^{2} )^{2}$

• As we know

$(a-b)^{2} =a^{2} -b^{2} -2ab$

• On applying the above formula, we get

$(a^{2} -b^{2} )^{2}$

$=(a^{2}) ^{2} -(b^{2} )^{2} -2a^{2} b^{2}$

$a^{4} -b^{4} -2a^{2}b^{2}$

Hence, the answer is $a^{4} -b^{4} -2a^{2}b^{2}$.