Question

find the following figure ABCD triangle the base Y the hypotenuse is to the perpendicular is one​

Answer 1

y is a side of triangle

1 is the other

2 is hypotenuse

thus,

2^2 = y^2 + 1^ 2

4 = y^2 + 1

4= y^2+1

y^2=3

y=√3..(ans(I))

(ii)

sin X= P/H

= y/2

= √3 /2...( ans (ii))

(iii)

(sec X - tanx )(sec X + tan X )

sec^2 X - tan^2 X

H/B^2 - P/B^2

2/1^2 -√3/1^2

4- 3

1..ans (iii)

P - perpendicular

B- Base

H- hypotenuse

( pls. do not forget to follow and thanks)

Answer 2

here are the answers for (i) (ii) (iii) questions......hope u will understand...