find the following pair of linear equation X + y = 16 and x minus y equal 4
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We have x+3y=16 ..... (1)
2x−y=4 ...... (2)
Equation (1) becomes, x = 16 - 3y ...... (3)
Substituting x in (2) we get, 2(16−3y)−y=4
⇒32−6y−y=4
−6y−y=4−32
−7y=−28
y=
−7
−28
=4
Substituting y=4 in (3) we get, x=16−3(4)
=16−12=4
∴ The solution is x = 4 and y = 4.
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