Question

find the following product (3x-4y+7) (x-y+3)​

Answer 1

Answer:

$3x^{2}+ 4y^{2} -7xy + 17x -19y + 21$

Step-by-step explanation:

$(3x-4y+7) (x-y+3) = 3x^{2} - 3xy + 9x - 4xy + 4y^{2} - 12y + 7x - 7y + 21 = 3x^{2}+ 4y^{2} -7xy + 17x -19y + 21$

Answer 2

Given,

• First Term = 3x–4y+7
• Second Term = x–y+3

To Find,

• The Product of (3x–4y+7) (x–y+3)

Solution,

$:\implies (3x - 4y + 7)(x - y + 3) \\ \\ :\implies (3x - 4y + 7)(x - y + 3) \\ \\ :\implies 3x(x - y + 3) - 4y(x - y + 3) + 7(x - y + 3) \\ \\ :\implies 3x \times x - y \times 3x + 3 \times 3x - 4y \times x - y \times ( - 4y) + 3 \times ( - 4y) + 7 \times x - 7 \times ( - y) + 7 \times 3 \\ \\ :\implies 3 {x}^{2} - 3xy + 9x - 4xy + 4 {y}^{2} - 12y + 7x + 7y + 21 \\ \\ :\implies 3 {x}^{2} + 4 {y }^{2} - 7xy + 16x - 5y + 21$

Required Answer,

$3 {x}^{2} + 4 {y }^{2} - 7xy + 16x - 5y + 21$