Question

find the foot of perpendicular form (1, -2) on the line 2x-3y+5=0.​

Answer 1

Answer:

simply substitute in this formula :- H-x/a= k-y/b=-(ax+by+c)/a square +b square

Step-by-step explanation:

h-1/2=k-(-2)/-3=-(2(1)-3(-2)+5)/4+9

". ". =-1

i.e. h-1/2=-1

h-1=-2

H=-1

i.e. k+2/-3=-1

k+2=3

k=1.

therefore required foot of perpendicular is (h,k)=(-1,1).

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