Math, asked by vijayendhran924, 5 months ago

Find the foot of the perpendicular drawn from (3,0)upon the straight line 5x+12y-41=0

Answers

Answered by midhunvenkat9030

3

Answer:

given that

L= 5x+12y-41=0

point(3,0)

foot point. q(h,k)

foot of the perpendicular from p to the straight line

h - x1÷a=k- y1÷b=-(ax1+by1+c)÷a×a+b×b

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