find the force experienced by a charged particle 3x10e-6C moving with a speed 300 Km/s along the direction of magnetic field of 20 Tesla
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Answer : No force i.e. 0
Explanation:
Magnetic force is given by, Fm = q (v x B)
= qvB sin∅
where q is the charge
v is velocity
B is magnetic field
and ∅ is the angle between v and B vectors
It is given that the particle is moving along the direction of magnetic field, therefore angle between them ∅ is 0
which implies sin ∅ = sin 0 = 0, which makes the force Fm equal to 0.
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