Question

find the force of attraction between two blocks lying 1 m apart. Let the mass of each block is 40 kg.

Answer 1

Answer:

Force=Gm1m2/r^2.

=6.67into10^-11into40into40/1into1

Answer 2

The force between masses is $F=1.067\times 10^{-7}\ N$.

Explanation:

Given that,

The mass of two blocks,  $m_1=m_2=40\ kg$

The distance between two blocks, r = 1 m

We need to find the force of attraction between two blocks. The force of attraction between masses is given by :

$F=\dfrac{Gm^2}{r^2}$

$F=\dfrac{6.67\times 10^{-11}\times (40)^2}{1^2}$

$F=1.067\times 10^{-7}\ N$

So, the force between masses is $F=1.067\times 10^{-7}\ N$. Hence, this is the required solution.

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