Find the force of gravitational attraction between the earth and a planet of mass m m=10^22 kg
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Answer:
Explanation:
Since, g = G (m1xm2)/r^2
= 6.67x10^-11 (5.97x10^24 x 10^22)/r^2
= 6.67x10^-11(5.97x10^46)/r^2
= 39.8199x10^55/r^2
= 40x10^55/r^2 N (approx.)
if the distance was given, then it would be more easy.
G is universal gravitational constant, m1 is mass of earth and m2 is mass of other planet, r is the distance between earth and that planet.
Answered by
0
Answer:
Since,
g = G (m1xm2)/r^2
= 6.67x10^-11 (5.97x10^24 x 10^22)/r^2
= 6.67x10^-11(5.97x10^46)/r^2
= 39.8199x10^55/r^2
= 40x10^55/r^2 N
if the distance was given, then it would be more easy.
G is universal gravitational constant, m1 is mass of earth and m2 is mass of other planet, r is the distance between earth and that planet.
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