Question

find the force required to move a train of mass 10^5kg up an incline 1 in 50 with an acceleration of 2m/s^2 coefficient of friction between the train and the rails is 0.005 ​

Answer 1

Answer:

F = Ma ,Where stooping force is 0.005*2 = 0.01 N and the applied all components force is 10^5 *2 so the final answer is 10^5-0.01N

Answer 2

Answer:

$13 \div \times 21286 + jddsd$