find the four numbers in A.P such that the sum is 38 and the product is 2856
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Answer:Let the numbers be: a−3d,a−d,a+d,a+3d
a−3d+a−d+a+d+a+3d=38
4a=38
∴a=9.5
(a−3d) 2+(a−d) 2 +(a+d) +(a+3d) =276
4a
2
+20d
2
=276
20d
2
=276−4(8)
2
=20
∴d=1
Therefore the 4 numbers are: a−3d,a−d,a+d,a+3d=8−3,8−1,8+1,8+3={5,7,9,11}
Step-by-step explanation:
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