Question

find the four numbers in A.P such that the sum is 38 and the product is 2856


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Answer 1

Answer:Let the numbers be: a−3d,a−d,a+d,a+3d

a−3d+a−d+a+d+a+3d=38

4a=38

∴a=9.5

(a−3d)  2+(a−d)  2 +(a+d)   +(a+3d)   =276

4a  

2

+20d  

2

=276

20d  

2

=276−4(8)  

2

=20

∴d=1

Therefore the 4 numbers are: a−3d,a−d,a+d,a+3d=8−3,8−1,8+1,8+3={5,7,9,11}

Step-by-step explanation: